The sum of ages of father and
his son is 60 years. If the difference between their ages is 40 years then find
the age of father and his son.
a) Father 40, son 10
b) Father 50, son 20
c) Father 50, son 10
d) Father 45, son 12
The sum and difference of two
numbers is 90 and 40 respectively. Find the number.
a) 65, 25
b) 40, 50
c) 20, 70
(x + 1/x)2 = ………..
a) x2 + 1/x2
b)x2 + 1/x2 – 2
c) x2 + 1/x2 +2
d) x2 + 1/x2 + 4
Solution:(x + 1/x)2 = (x)2+1/x2 + 2(x) (1/x)
= x2 + 1/x2 +2
a3 + 3ab(a+b) +b3 = …………
a) 3(a+b)2
b)(3a+3b)2
c) (a+b)3
d)3(a+b)3
If x + y=10, x – y = 10, then the value of x will be…….
a) 0
b) 5
c) 10
d) 20
Solution:x + y = 10
x – y = 10
2x = 20 x= 20/2 = 10
If we eliminate ‘t’ from 3t = x, and 2at = y then equal to…………..
a) x + y = 0
b) 2ax – 3y = 0
c) y/2a + x/3
d) None of these
Solution: 3t=x t=x/3
2at= y t=y/2a (t = t)
x/3 = y/2a 2ax = 3y 2ax–3y=0
Factorize 8x3 – 2xy2
a)2x(2x +y) (2x – y)
b) (2x2 - 2xy)2
c)(2x3 - 2xy)2
d)(2x)3 + 2x(y)2
Solution:8x3 – 2xy2
2x (4x2 – y2) 2x ((2x)2 - (y)2)
2x(2x + y) (2x – y)
